The enthalpies for the following reactions at 25- C are given- 1-2 H 2 g -1-2 O 2 g - OH g - H -10-06 K calH 2 g - 2 H g - - H -104-18 K calO 2 g - 2 O g - H -118-32 K calCalculate the OH bond energy in the O - H groupA- -100-19 K calB- 100-19 K calC- 101-19 K calD- -101-19 K cal

The correct option is D 101.19 K cal H(g) + O(g) → O H(g) Required equation Given: 1/2 H_2 (g) + 1/2 O_2 (g) → OH(g); H = + 10.06 K cal H(g) →1/2H_2 (g ...

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Standard XII

Chemistry

Enthalpy

The enthalpie...

Question

The enthalpies for the following reactions at 25°C are given.
$\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); △ H = 10.06 K c a l$
$H_{2} (g) \to 2 H (g); △ H = 104.18 K c a l$
$O_{2} (g) \to 2 O (g); △ H = 118.32 K c a l$

Calculate the OH bond energy in the O - H group

100.19 K cal

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101.19 K cal

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-101.19 K cal

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-100.19 K cal

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Solution

The correct option is C
-101.19 K cal

H(g) + O(g) $\to$ O - H(g) Required equation
Given: $\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); △ H = + 10.06 K c a l$
$H (g) \to \frac{1}{2} H_{2} (g); △ H = - 52.09 K c a l$
$O (g) \to \frac{1}{2} O_{2} (g); △ H = - 59.16 K c a l$

Adding them we get $H (g) + O (g) + (O H) (g) △ H = - 101.19 K c a l$

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Similar questions

The enthalpies for the following reactions at 25°C are given.
$\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); △ H = 10.06 K c a l$
$H_{2} (g) \to 2 H (g); △ H = 104.18 K c a l$
$O_{2} (g) \to 2 O (g); △ H = 118.32 K c a l$

Calculate the OH bond energy in the O - H group

Q. The enthalpies for the following reactions at

25^{o} C

are given:

\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); Δ H = 10.06 k c a l

H_{2} (g) \to 2 H (g); Δ H = 104.18 k c a l

O_{2} (g) \to 2 O (g); Δ H = 118.32 k c a l

Calculate the

O - H

bond energy in the

O H

group.

Q. The average O-H bond energy with the help of following data is:

(1) 2 H (g) ⟶ H_{2} (g); Δ H = - 435.0 {kJ mol}^{- 1}

(2) O_{2} (g) ⟶ 2 O (g); Δ H = + 489.6 {kJ mol}^{- 1}

(3) \frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ O H; Δ H = - 42.09 {kJ mol}^{- 1}

Calculate the enthalpy of the following reaction. $H_{2} C = C H_{2} (g) + H_{2} (g) \to C H_{3} - C H_{3} (g)$

The bond energies of C - H, C - C, C = C & H - H are 99, 83, 147 & 104 Kcal respectively.

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The enthalpies for the following reactions at 25°C are given. 12 H2(g) + 12 O2(g)→OH(g); △H = 10.06 K cal H2(g)→2H(g); △H = 104.18 K cal O2(g)→2O(g); △H = 118.32 K cal Calculate the OH bond energy in the O - H group

The correct option is C -101.19 K cal H(g) + O(g) → O - H(g) Required equation Given: 12 H2(g) + 12O2(g)→OH(g); △H=+10.06 K cal H(g)→12H2(g);△H=−52.09 K cal O(g)→ 12 O2(g); △H = −59.16 K cal Adding them we get H(g) + O(g)+ (OH)(g) △H = −101.19 K cal

The enthalpies for the following reactions at 25°C are given.
$\frac{1}{2} H_{2} (g) + \frac{1}{2} O_{2} (g) \to O H (g); △ H = 10.06 K c a l$
$H_{2} (g) \to 2 H (g); △ H = 104.18 K c a l$
$O_{2} (g) \to 2 O (g); △ H = 118.32 K c a l$

Calculate the OH bond energy in the O - H group