You visited us 1 times! Enjoying our articles? Unlock Full Access!

Heat of Formation

The enthalpie...

Question

The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283 k J m o l^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is

−676.5 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

676.5 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

110.5 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

−110.5 kJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
−110.5 kJ

(i) $C + O_{2} ⇋ C O_{2}$ , $Δ H = - 393.5 K J m o l^{- 1}$

(ii) $C O + \frac{1}{2} O_{2} ⇋ C O_{2}$ , $Δ H = - 283.0 k J m o l^{- 1}$

Operating (i) - (ii), we have

$C + \frac{1}{2} O_{2} ⇋ C O$ , $Δ H = - 110.5 k J m o l^{- 1}$

Suggest Corrections

125

Similar questions

The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283$ kJ mol $^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is:

Q. The enthalpies of combustion of carbon and carbon monoxide are

393.5

and

- 283

k J {m o l}^{- 1}

respectively. The enthalpy of formation of carbon monoxide per mole is:

Q. The enthalpy of combustion of carbon and carbon monoxide are

- 393.5

and

- 283 k J / m o l

respectively. The enthalpy of formation of carbon monoxide per mole is:

Q. The enthalpies of formation of

C O

and

C O

_{2}

are

- 110.5 k J

mol

^{- 1}

and

- 393.5 k J

mol

^{- 1}

respectively. The enthalpy of combustion of carbon monoxide is

Q. The enthalpies of combustion of Carbon and Carbon monoxide in excess of oxygen at

298 K

and constant pressure are

- 393.5

and

- 283.0 k J m o l^{- 1}

, respectively. Calculate the heat of formation of Carbon monoxide at constant volume.

Join BYJU'S Learning Program

The enthalpies of combustion of carbon and carbon monoxide are −393.5 and −283 kJ mol−1 respectively. The enthalpy of formation of carbon monoxide per mole is

The correct option is D −110.5 kJ (i) C + O2 ⇋ CO2, Δ H = −393.5 KJmol−1 (ii) CO + 12O2 ⇋ CO2, Δ H = −283.0 kJmol−1 Operating (i) - (ii), we have C + 12O2 ⇋ CO, ΔH = −110.5 kJmol−1

The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283 k J m o l^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is

The correct option is D
−110.5 kJ

(i) $C + O_{2} ⇋ C O_{2}$ , $Δ H = - 393.5 K J m o l^{- 1}$

(ii) $C O + \frac{1}{2} O_{2} ⇋ C O_{2}$ , $Δ H = - 283.0 k J m o l^{- 1}$

Operating (i) - (ii), we have

$C + \frac{1}{2} O_{2} ⇋ C O$ , $Δ H = - 110.5 k J m o l^{- 1}$