The enthalpy and entropy change for a chemical reaction are -2-5-10-3cal and 7-4 cal deg-1 respectively- Predict whether the nature or reaction at 298K is-

The correct option is B spontaneous Δ H= 2.5× 10 ^ 3 cal Δ S=7.4cal/deg T=298K= 25 ^ 0 c For spontaneous reaction, #160; Δ G must be less ...

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Standard XII

Chemistry

Heat of Reaction

The enthalpy ...

Question

The enthalpy and entropy change for a chemical reaction are $- 2.5 \times 10^{- 3} c a l$ and $7.4 c a l$ ${d e g}^{- 1}$ respectively. Predict whether the nature or reaction at $298 K$ is:

spontaneous

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reversible

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irreversible

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non-spontanesous

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Solution

The correct option is B spontaneous
$Δ H = - 2.5 \times 10^{- 3} c a l$
$Δ S = 7.4 c a l / d e g$
$T = 298 K = 25^{0} c$
For spontaneous reaction, $Δ G$ must be less than 0.
$Δ G = Δ H - T Δ S$
$= - 2.5 \times 10^{- 3} - (25 \times 7.4)$
$Δ G = - 185 c a l < 0$
Therefore, the reaction is spontaneous.

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The enthalpy and entropy change for a chemical reaction are −2.5×10−3cal and 7.4 cal deg−1 respectively. Predict whether the nature or reaction at 298K is:

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The enthalpy and entropy change for a chemical reaction are $- 2.5 \times 10^{- 3} c a l$ and $7.4 c a l$ ${d e g}^{- 1}$ respectively. Predict whether the nature or reaction at $298 K$ is: