wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The enthalpy change for a given reaction at 298 K is −xcal/mol. If the reaction occurs spontaneously at 298 K, the entropy change at that temperature:

A
Can be negative but numerically larger than x/298calK1mol1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Can be negative but numerically smaller than x/298calK1mol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Cannot be negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cannot be positive
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Can be negative but numerically larger than x/298calK1mol1
Solution:- (B) Can be negative but numerically smaller than x298cal/Kmol
As we know that,
ΔG=ΔHTΔS
For spontaneity,
ΔG<0
ΔHTΔS<0
Given:- ΔH=xcal/molveT=298K
Therefore,
For ΔG<0ΔS can be negative but the numerical value must be less than x298cal/Kmol.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rate Constant
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon