The enthalpy change for a given reaction at 298K is −xJmol−1(x being positive) If the reaction occurs spontaneously at 298K, the entropy change at that temperature :
A
Can be negative but numerically larger than x298
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Can be negative but numerically smaller than x298
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Cannot be negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cannot be positive
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Can be negative but numerically smaller than x298 For spontaneous reaction ΔG should be negative. we know that ΔG=ΔH−TΔS.