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Enthalpy

The enthalpy ...

Question

The enthalpy change for $C H_{4} (g) ⟶ C + 4 H$ is $1656 k J m o l^{- 1}$ . The average bond energy of $C - - H$ is $414 k J m o l^{- 1}$ .

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Solution

In this reaction, 4 C-H bonds are formed and no other bond is formed.

Hence, the average bond energy of C-H is one-fourth of the enthalpy change for the reaction.

$= \frac{1656 k J / m o l}{4} = 414 k J / m o l$

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