The enthalpy change for the following reaction, $N a O H (a q) + H C l (a q) ⟶ N a C l (a q) + H_{2} O (l)$ is -57 kJ. Predict the value of the enthalpy change in the following reaction:
$B a (O H)_{2} + H_{2} S O_{4} (a q) ⟶ B a S O_{4} (s) + 2 H_{2} O (l)$

- 57 k J

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- 76 k J

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- 114 k J

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- 228 k J

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Solution

The correct option is B $- 114 k J$
In the reaction, $N a O H (a q) + H C l (a q) ⟶ N a C l (a q) + H_{2} O (l)$ , one equivalent of hydrogen ions is neutralized with one equivalents of hydroxide ions. The enthalpy change is -57 kJ.
In the reaction $B a (O H)_{2} + H_{2} S O_{4} (a q) ⟶ B a S O_{4} (s) + 2 H_{2} O (l)$ , two equivalents of hydrogen ions are neutralized with 2 equivalents of hydroxide ions . The enthalpy of neutralization is $2 \times (- 57 k J) = - 114 k J$

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The enthalpy change for the following reaction, NaOH(aq)+HCl(aq)⟶NaCl(aq)+H2O(l) is -57 kJ. Predict the value of the enthalpy change in the following reaction:Ba(OH)2+H2SO4(aq)⟶BaSO4(s)+2H2O(l)

The enthalpy change for the following reaction, $N a O H (a q) + H C l (a q) ⟶ N a C l (a q) + H_{2} O (l)$ is -57 kJ. Predict the value of the enthalpy change in the following reaction:
$B a (O H)_{2} + H_{2} S O_{4} (a q) ⟶ B a S O_{4} (s) + 2 H_{2} O (l)$