wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The enthalpy change for the reaction H2(g)+C2H4(g)C2H6(g) is:

The bond energies are, HH=103, CH=99, CC=80 and C=C=145 K cal mol1

A
10 Kcalmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
+10 Kcalmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
30 Kcalmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
+30 Kcalmol1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D +30 Kcalmol1
H2 has a sigle HH bond. So ΔfHH2=103kcalmol1
C2H4 has structure HC|H=C|HH So, ΔfH=4×BECH+BEC=C
ΔfHC2H4=4×99+145=541kcalmol1
C2H6 has 6 CH bonds and one CC bond. So, ΔfHC2H6=6×99+80=674kcalmol1
Enthalpy change for the given reaction ΔH=674[541+103]
ΔH=+30kcalmol1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bond Parameters
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon