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Enthalpy of Combustion

The enthalpy ...

Question

The enthalpy change involved in the oxidation of glucose is $- 2880 k J m o l^{- 1}$ 25% of this energy is available for muscular work. If 80 kJ of muscular work is needed to walk one km, what is the maximum distance that a person will walk after eating 120g glucose?

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Solution

$120 g g l u c o s e = \frac{120 g}{180 g / m o l} = 0.67 m o l$ .
The energy available for muscular work $= 2880 k J / m o l \times 0.67 m o l \times 0.25 = 480 k J$ .
The maximum distance that can a person walk $\frac{480 k J}{80 k J / k m} = 6 k m$

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