wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The enthalpy change involved in the oxidation of glucose is -2880 kJ mol1. Twenty five percent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometer, what is the maximum distance that a person will be able to walk after eating 125 g of glucose?

A
5 km
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7.25 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.25 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5 km
As only 25% of the energy is available for muscular work
So,
Energy available for muscular work =25100×2880=720 kJ/mol
Molar mass of glucose = 180 g
Moles of glucose in 125 g of glucose = 125180 mol

Energy available for muscular work from 125 g of glucose,
= Moles× Energy per mole
=125180×720=500 kJ
100 kJ of muscular work is needed to walk one kilometer
Distance travelled =500100=5 km.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon