The enthalpy change involved in the oxidation of glucose is 2880 kJ/mol. $25 %$ of this energy is available for muscular work. If 100 kJ of muscular work is required to walk 1 km, calculate the maximum distance that can be covered by a person who as consumed 120 g of glucose

7.9 km

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9.7 km

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4.8 km

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8.4 km

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Solution

The correct option is C 4.8 km
Energy released by 120 g $[\frac{120}{80} m o l e s] o f g l u c o s e = 2880 \times \frac{120}{80} = 1920 k J$
Energy available for muscular work = $\frac{25}{100} \times 1920 = 480 k J$
$100 k J o f e n e r g y i s r e q u i r e d t o w a l k = 1 k m$
$480 k J o f e n e r g y i s r e q u i r e d t o w a l k = 4.8 k m$

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