Question

The enthalpy change involved in the oxidation of glucose is $-28850kJ.mo{l}^{-1}$. $25$% of this energy is available for muscular work. If $100$ kJ of muscular work is needed to walk one kilometer. What is the maximum distance that a person will be able to walk after consuming $120$ gm of glucose?

• A. $4.8$ km
• B. $9.6$ km
• C. $2.4$ km
• D. $7.2$ km

Answer 1

The correct option is A $4.8$ km

1 mole of Glucose, $C_6{H}_{12}{O}_6$ = $180$ gm

$\therefore 120$ gm glucose = $\frac{2}{3}$ moles of glucose.

As $2880KJ$ of energy is released by 1 mole of glucose.

Energy released = $\frac{2\times 2880}{3}$= $1920KJ$

$25$% of $1920$ kJ is available for muscular work.

$\therefore 480KJ$ is available for muscular work.

Given that - $100$ kJ is used per km.

The distance travelled is $480/100$ = $4.8km$

Hence, option $A$ is correct.