CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

The enthalpy changes for the following processes are listed below:
Cl2(g)2Cl(g);ΔHo=242.3kJmol1
I2(g)2I(g);ΔHo=151.0kJmol1
ICl(g)I(g)+Cl(g);ΔHo=211.3kJmol1
I2(s)I2(g);ΔHo=62.76kJmol1
Given that the standard states for iodine and chlorine are I2(s) and Cl2(g), the standard enthalpy of formation for ICl(g) is:

A
14.6 kJmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
26.8 kJmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16.8 kJmol1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
244.8 kJmol1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 16.8 kJmol1
12I212Cl2(g)ICl(g)
ΔH1Cl=[12ΔHI2(s)I2(g)+12ΔHII+12ΔHClCl]
[ΔHICl]
=[12×62.76+12×1.51.0+12×242.3][2.11.3]
=16.83KJ/mol
option (C) is correct.

1113967_646688_ans_a03690214cd247f8819ac6274710a492.jpg

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon