The enthalpy of a certain reaction at 273K is −20.75kJ.The enthalpy of same reaction at 373K (if heat capacities of reactants and products is same) will be:
A
−2075kJ
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B
2075kJ
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C
Zero
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D
−20.75×337273kJ
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Solution
The correct option is C−2075kJ From Kirchoff's equation ΔH2−ΔH1T2−T1=ΔCp As both have same heat capacities, ΔCp=0 or ΔH2=ΔH1∴ΔH2=−20.75kJ