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Enthalpy

The enthalpy ...

Question

The enthalpy of atomisation of $C H_{4}$ and $C_{2} H_{6}$ are 360 and 620 k cal $m o l^{- 1}$ respectively. The C - C bond energy is expected to be ?

A

$210 k c a l m o l^{- 1}$

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B

$130 k c a l m o l^{- 1}$

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C

$180 k c a l m o l^{- 1}$

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D

$80 k c a l m o l^{- 1}$

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Solution

The correct option is D
$80 k c a l m o l^{- 1}$

$C H_{4 (a q)} \to C_{(g)} + 4 H_{(g)}^{'} Δ H = 360 k c a l$
Hence, C - H bond energy $= \frac{360}{4} = 90 k c a l m o l^{- 1}$
Hence, $H_{C - C} + 6 H_{C - H} = 620$
Or $H_{C - C} = 620 - 6 H_{C - H} = 620 - 6 \times 90 = 80 k c a l$

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The enthalpy of atomisation of $C H_{4}$ and $C_{2} H_{6}$ are 360 and 620 k cal $m o l^{- 1}$ respectively. The C - C bond energy is expected to be ?

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