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Enthalpy of Combustion

The enthalpy ...

Question

The enthalpy of combustion of $H_{2}$ , cyclohexene $(C_{6} H_{10})$ and cyclohexane $(C_{6} H_{12})$ are -241, -3800 and -3920 kJ/mol respectively. Heat of hydrogenation of cyclohexene is:

-121 kJ per mol

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+121 kJ per mol

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+242 kJ per mol

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-242 kJ per mol

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Solution

The correct option is A -121 kJ per mol
The equations formed by the given data:
$\begin{matrix} H_{2} + \frac{1}{2} O_{2} \to H_{2} O & - 241 k J m o l^{- 1} . . . . . . . . . . . (1) C_{6} H_{10} + \frac{17}{2} O_{2} \to 6 C O_{2} + 5 H_{2} O & - 3800 k J m o l^{- 1} . . . . . . . . . . . . (2) C_{6} H_{12} + 9 O_{2} \to 6 C O_{2} + 6 H_{2} O & - 3920 k J m o l^{- 1} . . . . . . . (3) \end{matrix}$
$Adding eqn (1) and (2) and subtracting (3)$ :
$C_{6} H_{12} + H_{2} \to C_{6} H_{12}$
Enthalpy of hydrogention is thus:
$Δ H_{H y d r o g e n .} = - 241 + (- 3800) - (- 3920) = - 121 k J m o l^{- 1}$

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The enthalpy of combustion of H2, cyclohexene (C6H10) and cyclohexane (C6H12) are -241, -3800 and -3920 kJ/mol respectively. Heat of hydrogenation of cyclohexene is:

The enthalpy of combustion of $H_{2}$ , cyclohexene $(C_{6} H_{10})$ and cyclohexane $(C_{6} H_{12})$ are -241, -3800 and -3920 kJ/mol respectively. Heat of hydrogenation of cyclohexene is: