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Enthalpy

The enthalpy ...

Question

The enthalpy of dissociation of $H_{3}$ is $954 k J / m o l$ and that of $P_{2} H_{4}$ is $1.485 M J$ ${m o l}^{- 1}$ . What is the bond enthalpy of the $P - P$ bond?

A

213 k J / m o l

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B

- 213 k J / m o l

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C

2757 k J / m o l

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D

None of these

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Solution

The correct option is C $213 k J / m o l$
$H_{3} \to 3 H Δ H_{b} = 954 k J / m o l$
$P_{2} H_{4} \to 2 P + 4 H Δ H_{b} = 1485 k J / m o l$
$Δ H_{b}$ for $P - P$ bond = $1485 - 954 \times 4 / 3 = 213 k J / m o l$
Hence, option A is correct

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