Question

# The enthalpy of formation of ammonia is $$-46.0\ kJ\ mol^{-1}$$. The enthalpy change for the reaction $$2NH_3(g)\rightarrow 2N_2(g)+3H_2(g)$$ is:

A
46.0 kJ mol1
B
92.0 kJ mol1
C
23.0 kJ mol1
D
92.0 kJ mol1

Solution

## The correct option is B $$92.0\ kJ\ mol^{-1}$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More