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Molar and Specific Heat Capacity

The enthalpy ...

Question

The enthalpy of formation of hypothetical $M g C l$ is $- 125 k J m o l^{- 1}$ and for $M g C l_{2}$ is $- 624 k J m o l^{- 1}$ . What is the enthalpy of the disproportionation of $M g C l$ .

392 k J m o l^{- 1}

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- 392 k J m o l^{- 1}

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- 767 k J m o l^{- 1}

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- 517 k J m o l^{- 1}

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Solution

The correct option is B $- 392 k J m o l^{- 1}$
i) $M g (s) + C l_{2} (g) ⟶ M g C l_{2} (s)$ $Δ H_{1} = - 642$
ii) $M g (s) + \frac{1}{2} C l_{2} (g) ⟶ M g C l (s)$ $Δ H_{2} = - 125$
iii) $2 M g C l ⟶ M g C l_{2} + M g$ $Δ H = ?$
$Δ H = Δ H_{1} - 2 Δ H_{2}$
$= - 642 - 2 \times (- 125) = - 392 k J m o l^{- 1}$

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