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Question

The enthalpy of formation of methane at constant pressure and 300K is 75.83KJ. What will be the heat of formation at constant volume? (R=8.3JK1mol1)


A

-73.34 kJ

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B

73.34 kJ

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C

72.34 kJ

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D

-72.34 kJ

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Solution

The correct option is A

-73.34 kJ


The equation for the formation of methane is
C(s) + 2H2(g)CH4(g); H = 75.83 kJ
n = 1 - 2 = -1 (only gaseous components are taken into account)
Given H=75.83KJ,R=8.3×103 kJK1 mol1,T=300K
The enthalpy change can be given by the equation:
H=U+nRT
U=HnRT
U=75.83(1×8.3×103×300)
U=75.83+2.49
U=73.34kJ


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