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Question

The enthalpy of formation of reaction :
2H2(g)+O2(g)2H2O(l) is ΔrHo=572 kJmol1
What will be the enthalpy of formation of H2O(l)?

A
286 kJmol1
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B
286 kJmol1
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C
1144 kJmol1
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D
1144 kJmol1
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Solution

The correct option is A 286 kJmol1
Given:2H2(g)+O2(g)2H2O(l) ΔrHo=572 kJmol1.

Enthalpy of formation is the enthalpy change of the reaction when one mole of the compound is formed from its element, i.e. we aim at
H2(g)+12O2(g)H2O(l) ΔrHo=?

this can be obtained if we divide given reaction by 2.
so, ΔfHo(H2O(l))=ΔrHo2=5722=286 kJmol1

hence, enthalpy of formation of H2O(l) is 286 kJmol1.

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