wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The enthalpy of fusion of ice is 6.02kJmol1. The heat capacity of water is 4.18Jg1C1. What is the smallest number of ice cubes at 0C, each containing one mole of water, that are needed to cool 500g of liquid water from 20C to 0C.

A
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
140
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 7
heat released to cool 500g water from 20C to 0C.
q=msΔT
=500×4.18×20=41800J
=41.8kJ
Number of moles of water(ice) that will melt to absorb 41.8kJ=41.86.02
=7.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Enthalpy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon