The enthalpy of fusion of ice is 6.02kJmol−1. The heat capacity of water is 4.18Jg−1C−1. What is the smallest number of ice cubes at 0∘C, each containing one mole of water, that are needed to cool 500g of liquid water from 20∘C to 0∘C.
A
8
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B
7
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C
140
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D
120
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Solution
The correct option is B 7 heat released to cool 500g water from 20∘C to 0∘C. q=msΔT =500×4.18×20=41800J =41.8kJ Number of moles of water(ice) that will melt to absorb 41.8kJ=41.86.02 =≈7.