The enthalpy of fusion of ice is 6-02 kJ mol -1- The heat capacity of water is 4-18 J g -1 C -1- What is the smallest number of ice cubes at 0-C- each containing one mole of water- that are needed to cool 500 g of liquid water from 20-C to 0-C-

The correct option is B 7heat released to cool 500 nbsp;g water from 20^∘C to 0^∘C . q = msΔ T = 500× 4.18× 20 = 41800 J = 41. ...

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Byju's Answer

Standard XII

Chemistry

Enthalpy

The enthalpy ...

Question

The enthalpy of fusion of ice is $6.02 k J m o l^{- 1}$ . The heat capacity of water is $4.18 J g^{- 1} C^{- 1}$ . What is the smallest number of ice cubes at $0^{\circ} C$ , each containing one mole of water, that are needed to cool $500 g$ of liquid water from $20^{\circ} C$ to $0^{\circ} C$ .

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Solution

The correct option is B 7
heat released to cool $500 g$ water from $20^{\circ} C$ to $0^{\circ} C$ .
$q = m s Δ T$
$= 500 \times 4.18 \times 20 = 41800 J$
$= 41.8 k J$
Number of moles of water(ice) that will melt to absorb $41.8 k J = \frac{41.8}{6.02}$
$=\approx 7$ .

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the enthaipy of fusion of ice is 6.02 kj/mole the heat capacity of water is 4.18 joule g^-1C^-1 what is the smallest number of ice cubes at 0⁰C each containing one mole of water that are needed to cool 500 g of liquid water from 20^oC - 30^oC

ans =7 how ?

Q. Chemical reactions are invariably associated with the transfer of energy either in the form of heat or light. In the laboratory,
heat changes in physical and chemical processes are measured with an instrument called Calorimeter. Heat change
in the process is calculated as

q = m s Δ T

........

s = s p e c i f i c h e a t

= c Δ T

.......

c = h e a t c a p a c i t y

Heat of reaction at constant volume is measured using bomb Calorimeter.

q_{V} = Δ U = i n t e r n a l e n e r g y c h a n g e

Heat of reaction at constant pressure is measured using bomb Calorimeter.

q_{P} = Δ H

q_{P} = q_{V} + P Δ V

Δ H = Δ U + Δ n R T

The enthalpy of fusion of ice is

6.02 k J m o l^{- 1}

. The heat capacity of water is

4.18 J g^{- 1} C^{- 1}

What is the smallest number of ice cubes at

0^{\circ} C

, each containing one mole of water, that is needed to cool

500 g

of liquid water from

20^{\circ} C

0^{\circ} C

Four cubes of ice at -10 ^oC weighing one gram each is taken out from the refrigerator and are put in 150 grams of water at 20 ^oC. What is the final temperature of water when thermal equilibrium is attained? Assume that no heat is lost to the outside and water equivalent of container is 46 g. (Specific heat capacity of water = 1 cal/g-^oC, Specific heat capacity of ice = 0.5 cal/g-^oC, Latent heat of fusion of ice = 80 cal/g-^oC)

Q. One mole of steam is condensed at