Question

The enthalpy of neutralisation of the given reaction is:

$H_{2}S{O}_4+2NaOH\to N{a}_{2}S{O}_4+2H_{2}O,y:kcal$

• A. $2ykcal$
• B. $-2ykcal$
• C. $+y/2kcal$
• D. $-y/2kcal$

Answer 1

The correct option is A $2ykcal$

As the each substrate of neutrilisation reaction is $2$ equivalent so-

Neutrilisation energy will be =$2\times y$

NOTE- We know that neutrilisation reaction is exothermic but as the question is asking for particular energy so we will not put the neagtive sign before the answer.