The enthalpy of neutralization of acetic acid and sodium hydroxide is -55.4 kJ. What is the enthalpy of ionisation of acetic acid?

-5.54 kJ

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+5.54 kJ

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+1.9 kJ

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-1.9 kJ

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Solution

The correct option is B -1.9 kJ
Given, $△ H_{n e u t r a l i z a t i o n} = - 55.44 J$
$△ H (H^{+} + O H^{-}) = - 57.3 K J$
$△ H_{n e u t r a l i z a t i o n} = △ H_{i o n i z a t i o n} + △ H (H^{+} + O H^{-})$
$- 55.4 K J = △ H_{i o n i z a t i o n} - 57.3 K J$
$△ H_{i o n i z a t i o n} = 1.9 K J$

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