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Standard XII

Chemistry

Heat of Reaction

The enthalpy ...

Question

The enthalpy of neutralization of HCN by NaOH is - 12.13 KJ ${m o l}^{- 1}$ . The enthalpy of ionisation of HCN will be :

4.519 kj

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45.10 kj

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451.9 kj

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45.19 kj

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Solution

The correct option is D 45.19 kj
-57.4 + X = -12.13 X= 45.19D is correct

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The enthalpy of neutralization of HCN by NaOH is - 12.13 KJ mol−1. The enthalpy of ionisation of HCN will be :

The correct option is D 45.19 kj-57.4 + X = -12.13 X= 45.19D is correct

The enthalpy of neutralization of HCN by NaOH is - 12.13 KJ ${m o l}^{- 1}$ . The enthalpy of ionisation of HCN will be :

The correct option is D 45.19 kj
-57.4 + X = -12.13 X= 45.19D is correct