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Question

The enthalpy of reaction for the reaction:

2H2(g)+O2(g)2H2O(l) is
ΔrHo=572 kJ mol1

What will be standard enthalpy of formation of H2O(l)?

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Solution

The standard enthalpy of formation of H2O(l) can be obtained by considering the following reaction:

H2(g)+12O2(g)H2O(l)

As ΔfHo is related to one mole of a compound formed at standard conditions

For the given reaction:

2H2(g)+O2(g)2H2O(l)
the standard enthalpy of reaction is ΔHor=572 kJ mol1,

So, on relating the given equation with earlier equation, the half of ΔHor will be the standard molar enthalpy of formation;

ΔfHo=12×ΔHor

=(5722) kJ mol1

ΔfHo=286 kJ mol1

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