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Application of Electrolysis

The enthalpy ...

Question

The enthalpy of sublimation of Aluminium is 330 kJ/mol. Its Ist, IInd and IIIrd ionization enthalpies are 580, 1820 and 2740 kJ respectively. How much heat has to be supplied (in kJ) to convert 13.5 gram of Aluminium into Al3+ ions and electrons at 298 K ?

A

5470

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B

3764

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C

4105

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D

2735

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Solution

The correct option is D
2735

Heat needed to be supplied per mole
= 330 + 580 + 1820 + 2740 = 5470 kJ
no. of moles of Al taken = $\frac{13.5}{27}$ = 0.5 mol
$\Rightarrow$ Heat required = 0.5 × 5470 kJ = 2735 kJ

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