The enthalpy of transition of C(diamond) to C(graphite) is (Given that the enthalpies of combustion of C(diamond) and C(graphite) are – 393.5 and – 395.4 kJ mol−1 respectively)
A
+ 1.9 kJ
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B
- 1.9 kJ
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C
3.8 kJ
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D
- 3.8 kJ
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Solution
The correct option is A + 1.9 kJ Our aim is: C(diamond)→C(graphite);ΔH=? The available data is : (i) C(diamond)+O2(g)→CO2(g);ΔH=–393.5kJ (ii) C(graphite)+O2(g)→CO2(g);ΔH=–395.4kJ Subtracting equation (ii) from equation (i) SubtractC(diamond)−C(graphite)→O;ΔH=(–393.5+395.4) Or C(diamond)→C(graphite);ΔH=+1.9kJ