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Question

The enthalpy of transition of C(diamond) to C(graphite) is (Given that the enthalpies of combustion of C(diamond) and C(graphite) are – 393.5 and – 395.4 kJ mol1 respectively)

A
+ 1.9 kJ
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B
- 1.9 kJ
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C
3.8 kJ
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D
- 3.8 kJ
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Solution

The correct option is A + 1.9 kJ
Our aim is:
C(diamond)C(graphite);ΔH=?
The available data is :
(i) C(diamond)+O2(g)CO2(g);ΔH=393.5kJ
(ii) C(graphite)+O2(g)CO2(g);ΔH=395.4kJ
Subtracting equation (ii) from equation (i)
SubtractC(diamond)C(graphite)O;ΔH=(393.5+395.4)
Or
C(diamond)C(graphite);ΔH=+1.9kJ

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