The enthalpy of vaporisation of liquid is 30KJ/mol and entropy of vaporisation is 75J/mol/k. The Boiling point of the liquid at 1 atm is

250 k

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400 k

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450 k

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600 k

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Solution

The correct option is B
400 k

$d S = \frac{d q_{r e v}}{T}$

Or, $75 = \frac{30 \times 10^{3}}{T}$ or, $T = 400 K$

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Similar questions

30 k J / m o l

75 J m o l^{- 1} K^{- 1}

1 a t m

Δ H = 30 k J m o l^{- 1}

Δ S = 75 J K^{- 1} m o l^{- 1}

109.3 j K^{- 1} m o l^{- 1}

40.77 k J m o l^{- 1}

35^{\circ} C

24.64 k J {m o l}^{- 1}

^{- 1}

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