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Question

The enthalpy of vapourisation of liquid water using the data
H2(g)+12O2(g)H2O(l);ΔH=285.77KJmol1
H2(g)+12O2(g)H2O(g);ΔH=241.84KJmol1

A
+43.93 KJ mol1
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B
-43.93 KJ mol1
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C
+527.61 KJ mol1
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D
-527.61 KJ mol1
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Solution

The correct option is A +43.93 KJ mol1
The thermochemical reactions are as given below.
H2(g)+12O2(g)H2O(l);ΔH=285.77KJmol1 ......(1)
H2(g)+12O2(g)H2O(g);ΔH=241.84KJmol1 ......(2)
The reaction (1) is reversed and added to the reaction (2) to obtain the reaction for the vapouisation of liquid water which is H2O(l)H2O(g)
Hence, the heat of vapourisation of liquid water is 241.84+285.77=43.93KJmol1

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