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Enthalpy

The enthalpy ...

Question

The enthalpy of vapourization of liquid is $30 k J m o l^{- 1}$ and entropy of vaporization is $75 k J / m o l$ . The boiling point of the liquid at 1 atm is

250 K

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400 K

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450 K

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600 K

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Solution

The correct option is B
400 K

$Δ S = \frac{Δ Q_{r e v}}{T}; 75 = \frac{30 \times 10^{3}}{T}$

$∴ T = 400 K$

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The enthalpy of vaporisation of liquid is 30KJ/mol and entropy of vaporisation is 75J/mol/k. The Boiling point of the liquid at 1 atm is

Δ H = 30 k J m o l^{- 1}

Δ S = 75 J K^{- 1} m o l^{- 1}

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