The entropy change can be calculated by using the expression ΔS=qrevT. When water freezes in a glass beaker, choose the correct statement amongst the following.
A
Δ S (system) decreases but Δ S (surroundings) remains the same
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B
Δ S (system) increases but Δ S (surroundings) decreases
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C
Δ S (system) decreases but Δ S (surroundings) increases
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D
Δ S (system) decreases but Δ S (surroundings) also decreases
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Solution
The correct option is DΔ S (system) decreases but Δ S (surroundings) increases Freezing is exothermic process. The heat released increases the entropy of surrounding. Randomness of water molecules decreases as they are converting into solid.