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Elevation in Boiling Point

The entropy c...

Question

The entropy change for vaporisation of a liquid is $109.3 j K^{- 1} m o l^{- 1}$ . The molar heat of vaporistion of that liquid is $40.77 k J m o l^{- 1}$ . Calculate the boiling points of that liquid.

270 K

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373 K

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250 K

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100 K

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Solution

The correct option is C $373 K$
At vaporization, $△ G = 0$ as vapor is in equilibrium with liquid state.
$∴ △ G = △ H - T △ S = 0$
$∴ T_{b} = \frac{△ H_{v a p}}{△ S_{v a p}} = \frac{40.77 \times 10^{3}}{109.3} = 373 K$

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