Question

The entropy change in the fusion of 1 mole of a solid melting at ${27}^{0}C$ (Latent heat of fusion, 2930J mo$l^{-1}$)is :

• A. 9.77$J{K}^{-1}{mol}^1$
• B. 10.73$J{K}^{-1}{mol}^1$
• C. 2930$J{K}^{-1}{mol}^1$
• D. 108.5$J{K}^{-1}{mol}^1$

Answer 1

Answer: (A)

9.77$J{K}^{-1}{mol}^1$

$\Delta S=\frac{q}{T}q=2930T=273+27=300\therefore \Delta S=\frac{2930}{300}=9.77{JK}^{-1}{mol}^{-1}$