The entropy of a crystalline substance at absolute zero on the basis of third law of thermodynamics should be taken as:
A
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
zero
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
different for different substances
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C zero The third law of thermodynamics was formulated by Nernst. It states that, "The entropy of a perfactly crystalline substance at absolute zero or zero kelvin is taken as zero".
ΔS=∫T0CPd(lnT)=2.303∫T0CPd(logT)
The ΔS is calculate by above formula of pure substance at different temperature.