Question

The entropy of a sample of a certain substance increases by $0.836J{K}^{-1}$ on adding reversibly 0.3344 J of heat at constant temperature. The temperature of the sample is:

• A. 0.4 K
• B. 2.5 K
• C. 0.016 k
• D. 0.3 k

Answer 1

Answer: (A)

0.4 K

$△G\ge △h-T△s$

$△F=\theta$

for reversibly reaction

$\therefore △h=T△S$

$△h=0.3344Joules$

$△S=0.836$

$\therefore T=\frac{△h}{△s}$

$=\frac{0.3344}{0.836}$

$\therefore T=0.4K$