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System, Surroundings, Intensive, Extensive Properties

The entropy o...

Question

The entropy of vaporization of benzene is $85 J K^{- 1} {m o l}^{- 1}$ . If $117$ g benzene vaporizes at its normal boiling point, calculate the entropy change of the surrounding.

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Solution

Entropy of vapourization of benzene $Δ s = 85 J k^{- 1} m o l^{- 1}$
Amunt of benzene $= 117 g$
Molar mass of benzene $(C_{6} H_{6}) = 78 g$
number of mole $= \frac{117}{78} = 1.5 m o l e$
Entropy charge of surrounding $= - 85 \times 1.5$
$= - 127.5 J K^{- 1}$

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