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Combustion Reactions

The entropy o...

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The entropy of vaporization of benzene is 85 JK^{-1}mol^{-1}. When 117 g benzene vaporizes at its normal boiling point then the entropy change of surrounding is : - (1) -85 JK^{-1} (2) -85 × 1.5 JK^{-1 } (3 ) 85 × 1.5 JK^{-1 }(4) None of these .

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Q. The entropy of vaporization of benzene is

85 J K^{- 1} {m o l}^{- 1}

117

g benzene vaporizes at its normal boiling point, calculate the entropy change of the surrounding.

Q. The entropy of vaporization of benzene is

85 J K^{- 1} {m o l}^{- 1}

117

benzene vaporizes at its normal boiling point, the entropy change of surrounding is:

Q. The entropy of vaporization of benzene is

85 J K^{- 1} m o l^{- 1} .

117 g

benzene vapourization:

Q. The entropy of vaporisation of a liquid is

58 J K^{- 1} m o l^{- 1}

100 g

of its vapor condenses at its boiling point of

123^{\circ} C

, the value of entropy change for the process is
(Molar mass of the liquid

= 58 {g mol}^{- 1}

)

Calculate entropy change for vaporization of 1 mole of liquid water to steam at $100^{\circ} C$ if $Δ H_{v}$ =40.8 kJ $m o l^{- 1}$ .

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