The enzyme carbonic anhydrase catalyzes the hydration of $C O_{2}$ . This reaction: $C O_{2} + H_{2} O \to H_{2} C O_{3}$ , is involved in the transfer of $C O_{2}$ from tissues to the lungs via the bloodstream.
One enzyme molecule hydrates $10^{6}$ molecules of $C O_{2}$ per second. How many kgs of $C O_{2}$ are hydrated in one hour in one liter by $1 \times 1^{- 6} M$ enzyme?

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Solution

number of molecule of ${C O}_{2}$ hydrated by enzyme in one hour = $10 (6) \times 3600$
Number of mole ${C O}_{2}$ hydrated by $10 (- 6) \times N a$ enzyme in one hour $= 3600 \times N a$
Let the weight of ${C O}_{2}$ be $x g$
then $x = \frac{3600 \times N a \times 44}{N a} = 158400 g = 158.4 K g$

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The enzyme essential for the transport of ${C O}_{2}$ as bicarbonate in the blood is

The enzyme essential for the transport of CO₂ as bicarbonate in the blood is

Assertion (A) $C O_{2}$ transport occurs very fast through RBCs.
Reason (R) Enzyme carbonic anhydrase is absent in blood plasma.

(i) C O_{2} + H_{2} O \to H_{2} C O_{3}

(i i) H_{2} C O_{3} \to H^{+} + H C O_{3}^{-}

(i i i) H_{2} C O_{3} \to H_{2} O + C O_{2}

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