Question

The eqivalent weight of $C{H}_4$ in the reaction $C{H}_4+2O_2\to C{O}_2+2H_{2}O$ is? $[M=mol.wt]$

• A. $\frac{M}{4}$
• B. $\frac{M}{8}$
• C. $\frac{M}{12}$
• D. $\frac{M}{16}$

Answer 1

Answer: (A)

$\frac{M}{4}$

Equivalent mass of $C{H}_4$ = atomic mass of C/ Valency + atomic mass of H/ Valency

= $\frac{12}{4}$ + $\frac{1}{2}$

= 3 + 1 = 4

As the molecular mass of $C{H}_4$ is 16 u

equivalent mass of $C{H}_4$ = 4 = $\frac{16}{4}$

= $\frac{M}{4}$