Question

The equatio of the plane which bisects the angle between the planes 3x-6y+2z+5=0 and 4x-12y+3z-3=0 which contains the origin is

• A. 33x-13y+32z+45=0
• B. x-3y+z-5=0
• C. 33x+13y+32z+45=0
• D. None of these

Answer 1

The correct option is D None of these

Equation of plane bisecting the angle containing origin is (making constant term of same sign)
$\frac{-3x+6y-2z-5}{\sqrt{3^2+6^2+2^2}}=+\left[\frac{4x-12y+3z-3}{\sqrt{4^2+{12}^2+3^2}}\right]or\frac{-3x+6y-2z-5}{7}=\frac{4x-12y+3z-3}{13}or67x-162y+47z+44=0$