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Question

The equation 2cos2(x/2)sin2x=x2+x2:0<xπ/2 has

A
no real solution
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B
one real solution
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C
more than real solution
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D
two real solution
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Solution

The correct option is A no real solution
Given equation is 2cos2(x2)sin2x=x2+x2,xπ9
LHS=2cos2(x2)sin2x<2
and RHS=x2+1x22
The equation has no real solution.

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