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Question

The equation 3cosx+4sinx=6 has .............solution

A
Finite
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B
Infinite
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C
One
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D
No
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Solution

The correct option is C No
3cosx+4sinx=6
acosx+bsinx[a2+b2],[a2+b2]

here, a=3 and b=4
So,
3cosx+4sinx[5,5]
So,
3cosx+4sinxcantgobeyond5

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