Question

The equation $3y^2+y+4=2(6x^2+y+2)$ where $y$ = $2x$ is satisfied by

• A. no value of $x$
• B. all values of $x$
• C. $x=0$ only
• D. all integral values of $x$ only
• E. all rational values of $x$ only

Answer 1

Answer: (C)

$x=0$ only

given equation is $3y^2$= $y$+$4$=$2$($6x^2$+$y$+$2$)

given $y=2x$

$12x^2$+$2x+4=2$($6x^2$+2$x$+$2$)

for $x=0$ this value satisfy.

so option $C$ is correct.