The equation 5t - 4 = 1 is satisfied when the value of t = 1.
True
In order to check whether the above equation 5t-4 =1 is satisfied for t =1, we simply put 1 in place of t, So substituting t = 1 in the equation , we get
LHS = 5× (1) - 4 =1 and RHS = 1.
Since, LHS=RHS, t =1 satisfies the equation 5t-4 =1.