The Equation $5 x^{4} - 3 x^{3} + 7 x^{2} - 4 x + 2 = 0$ is of the type

Quadratic

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Linear

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Reciprocal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D None
The highest power of $x$ in this equation is $4$ , so this is a $4 t h$ order equation.
Thus, it is neither linear nor quadratic.
Now to be reciprocal equation the multiplication of roots should be $1$ and in the given equation
Multiplication of roots is $\frac{e}{a} = \frac{2}{5}$
So this not a reciprocal equation
Hence, option D is correct.

Suggest Corrections

Similar questions

2 x^{4} - 3 x^{3} + 7 x^{2} - 3 x + 2 = 0

2 x^{4} - 3 x^{3} + 7 x^{2} + 3 x - 2 = 0

x^{5} + 5 x^{4} + 3 x^{3} + x^{2} + x - 1 = 0

x^{4} - 3 x^{3} + 7 x^{2} + 5 x - 2 = 0

7 x^{2} + 4 x - 20 = 0

Join BYJU'S Learning Program