The equation -7 x 2-3-0 hasA- two rational rootsB- no real rootsC- only one irrational rootD- two irrational roots

The correct option is D two irrational roots nbsp; 7x^2+3=0 ⇒ 7x^2=3 ⇒ x=±√(37) nbsp; nbsp; So both the roots of the equation are irrational ...

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Standard XIII

Mathematics

Nature of Roots

The equation ...

Question

The equation $- 7 x^{2} + 3 = 0$ has

two rational roots

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two irrational roots

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no real roots

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only one irrational root

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Solution

The correct option is B two irrational roots
$- 7 x^{2} + 3 = 0$
$\Rightarrow 7 x^{2} = 3$
$\Rightarrow x = \pm \sqrt{\frac{3}{7}}$
So both the roots of the equation are irrational

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Question 8
The quadratic equation $2 x^{2} - \sqrt{5} x + 1 = 0$ has
(A) two distinct real roots
(B) two equal real roots
(C) no real roots
(D) more than 2 real roots

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Nature of Roots

Standard XIII Mathematics

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The equation −7x2+3=0 has

The correct option is B two irrational roots −7x2+3=0 ⇒7x2=3 ⇒x=±√37 So both the roots of the equation are irrational

The equation $- 7 x^{2} + 3 = 0$ has

The correct option is B two irrational roots
$- 7 x^{2} + 3 = 0$
$\Rightarrow 7 x^{2} = 3$
$\Rightarrow x = \pm \sqrt{\frac{3}{7}}$
So both the roots of the equation are irrational