The equation 8x2+8xy+2y2+26x+13y+15=0 represents a pair of straight lines.The distance between them is
The distance between the parallel straight lines given by ax2+2hxy+by2+2gx+2fy+c=0 is 2√g2−aca(a+b).
Here, a = 8, b= 2 , c= 15, g = 13.
So, required distance = 2√169−12080=72√5.