The correct options are
A Only one solution
B Exactly one solution in (0, 1)
D No solution in (-1, 0)
As cos−1x≥0 ∀ x ϵ [−1,1] and tan−1x>0,∀ x in(0,∞)
So, solution must be a positive number only
Now, cos−1x=tan−1x
cos−1x=cos−1(1√1+x2)⇒x2=11+x2
x4+x2−1=0⇒x2=−1±√52⇒x=√−1+√52(0,1)