The equation (cosp−1)x2+(cosp)x+sinp=0, where x is a variable with real roots. then the interval of p may be any one of the following.
A
(0,2π)
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B
(−π,0)
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C
(−π2,π2)
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D
(0,π)
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Solution
The correct option is C(0,π) for real roots , discriminant is greater than or equal to zero that is cos2p−4sinp(cosp−1)≥0 now cosp−1≤0 so if sinp≥0 then our task is done now sinp≥0 holds in first and second quadrants.