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Question

The equation (cosp1)x2+(cosp)x+sinp=0, where x is a variable with real roots. then the interval of p may be any one of the following.

A
(0,2π)
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B
(π,0)
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C
(π2,π2)
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D
(0,π)
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Solution

The correct option is C (0,π)
for real roots , discriminant is greater than or equal to zero
that is cos2p4sinp(cosp1)0
now cosp10
so if sinp0 then our task is done
now sinp0 holds in first and second quadrants.

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